Well since we know the diameter's endpoints the centre of the circle must be the midpoint of the 2 points.
We can use the midpoint formula:
Sub in the values to find the midpoint
Guys, i have one question in math.
here it it.
The diameter of a circle has the endpoints (9,5) and (3,-8). Find the center of the circle and at least two other points on the circle.
The big E thing is in the poster's signature, it is not part of the response!
You have been shown how to find the centre in post #2 and from this apply the radius from post #4 to this centre point, here's two easy solutions, given (x,y) is the centre and r your radius then you have (x+r,y) and (x,y+r)
the slope diagramof the given diameter points is 13/6. Its radius slope diagram is 6.5/3.
A diameter perpendicular to the given diameter has a slope of -6/13 and its radius slope diagram is -3/6.5.
Working with these new radius slopes and starting at the circle center the end points on the circle are determined to be (-.5,1.5) and (12.5,-4.5) by moving 6.5 points right and left of center and 3 points up and down of center
Do you know the formula for distance between two points?
The distance from to is .
You can use that to find the distance form (6, 1.5), the center of the circle, to either (9, 5) or (3, -8), the radius of the circle, then find values of (x, y) such that the distance from (x, y) to (6, -1.5) is that radius. (There will be an infinite number of such points, of course. Choose some convenient value for x and determine y satifying that equation.)