Hi, I need to solve for x in the following two equations:
(x-1/x)^2 - 77/12 (x-1/x) + 10 = 0
[I expanded out to get (x^2 + 1/x^2 - 77x/12 + 77/12x + 8). Then I used the factor theorem to plug in possible x's, and found that (x-4) is a factor. However, I don't know where to go from there, or if what I've done so far is correct.]
(3x-5)(3x+1)^2(3x+7) + 68 = 0
Thank you for any help!