(a) I got 2x^2 - 9x + 4 = 0

(b) I can't do

(c) x = 1/2 or x = 4

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- Jul 8th 2007, 02:49 AMGAdamsGraph Equation
(a) I got 2x^2 - 9x + 4 = 0

(b) I can't do

(c) x = 1/2 or x = 4 - Jul 8th 2007, 03:37 AMjanvdl
For a)

Simply multiply through with $\displaystyle x $ and take all the terms over to the left hand side of the equal sign.

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For b)

$\displaystyle xy = 4 $ ----- (1)

$\displaystyle 2x^2 - 9x + 4 = 0 $

$\displaystyle -(2x^2 - 9x) = 4 $ ------- (2)

Set (1) = (2)

$\displaystyle -(2x^2 - 9x) = xy $

$\displaystyle y = -(2x - 9) $

$\displaystyle y = -2x + 9 $

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For c)

$\displaystyle 2x^2 - 9x + 4 = 0 $

$\displaystyle (2x - 1)(x - 4) = 0 $

$\displaystyle x = \frac{1}{2} \ or \ x = 4 $