Does anyone know the correct method for solving $\displaystyle 4x^2+2x = 8$ ? Thanks in advance.
Since 2 is a common factor you can divide through by 2: $\displaystyle 2x^2+x=4$
Move the 4 over to the left hand side: $\displaystyle 2x^2+x-4 = 0$
You can then solve the quadratic is your favourite way (I suggest the formula)