x is $\displaystyle \frac{3}{13}$

Im not sure where i went wrong

$\displaystyle \frac{15x}{4}$= $\displaystyle \frac{9}{4}$ - $\displaystyle \frac{3-x}{2}$

LCD first so...

$\displaystyle \frac{15x}{4}$= $\displaystyle \frac{9}{4}$ - $\displaystyle \frac{6-2x}{4}$

solve...

15x=9-6-2x

15x=3-2x

17x=3

x=$\displaystyle \frac{3}{17}$

on a side note, how would i solve

$\displaystyle 15(\frac{3x}{5}$ - $\displaystyle \frac{x}{3})$