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Math Help - Distance Rate Time Problem- Math 011 Quadratics

  1. #1
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    Red face Distance Rate Time Problem- Math 011 Quadratics

    During the first part of a trip, Carol travels 200 km at a certain speed. For the next 150 km she travels 5 km/h faster. If she took 2 hours and 52 minutes to complete her 350 km trip, what was her speed in each leg of her journey?

    Any assistance is soo appreciated, im really desperate for any kind of help here
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  2. #2
    MHF Contributor Unknown008's Avatar
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    The time she takes to cover the first trip is given by:

    t_1 = \dfrac{200}{v}

    where v is the speed.

    The time she took for th second trip is given by:

    t_2 = \dfrac{150}{v + 5}

    Total, t_1 + t_2 = 2h\ 35\ min = \frac{31}{12}\ h

    Can you solve this by substituting t1 and t2 in the last equation, for v and then you find v + 5 km/h
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    thank you so much!
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  4. #4
    MHF Contributor Unknown008's Avatar
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    You're welcome
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