1. ## Inequalities

This seems straightforward. Is it really as simple as drawing a line from -2 to 3 horizontally parallel to the existing one on the diagram?

2. Oops! Forgot to attach the question!

Oops! Forgot to attach the question!
"the following integers" are missing. a lot of integers are like children, you have to keep close watch on them because they tend to wander and get lost

4. Not naughty, just shy!

-2, -1, 0, 1, 2, 3

Not naughty, just shy!

-2, -1, 0, 1, 2, 3
lucky you. usually the integers i work with are naughty. i'd draw the inequality $\displaystyle -2 \leq x \leq 3$

you could actually draw any inequality ranging from $\displaystyle -4 \leq x \leq 6$ but encompassing the region $\displaystyle -2 \leq x \leq 3$

do you know how to do that?

6. Originally Posted by Jhevon
lucky you. usually the integers i work with are naughty. i'd draw the inequality $\displaystyle -2 \leq x \leq 3$

you could actually draw any inequality ranging from $\displaystyle -4 \leq x \leq 6$ but encompassing the region $\displaystyle -2 \leq x \leq 3$

do you know how to do that?
Well, I would draw a line from the point 3 to just after -2.

yes the black spot, it was actually a circle that was shaded in. we shade the circle if we have $\displaystyle \geq$ or $\displaystyle \leq$, we leave it unshaded if we have $\displaystyle >$ or $\displaystyle <$