1. ## Inequalities

This seems straightforward. Is it really as simple as drawing a line from -2 to 3 horizontally parallel to the existing one on the diagram?

2. Oops! Forgot to attach the question!

Oops! Forgot to attach the question!
"the following integers" are missing. a lot of integers are like children, you have to keep close watch on them because they tend to wander and get lost

4. Not naughty, just shy!

-2, -1, 0, 1, 2, 3

Not naughty, just shy!

-2, -1, 0, 1, 2, 3
lucky you. usually the integers i work with are naughty. i'd draw the inequality $-2 \leq x \leq 3$

you could actually draw any inequality ranging from $-4 \leq x \leq 6$ but encompassing the region $-2 \leq x \leq 3$

do you know how to do that?

6. Originally Posted by Jhevon
lucky you. usually the integers i work with are naughty. i'd draw the inequality $-2 \leq x \leq 3$

you could actually draw any inequality ranging from $-4 \leq x \leq 6$ but encompassing the region $-2 \leq x \leq 3$

do you know how to do that?
Well, I would draw a line from the point 3 to just after -2.

Well, I would draw a line from the point 3 to just after -2.
that's fine. but note if you draw the line from point 3, you'd have to shade the circle, if you're going to draw it extending past -2, then you don't have to shade that one

8. Shade the circle? I don't understand. Do you mean that black spot?

Originally Posted by Jhevon
that's fine. but note if you draw the line from point 3, you'd have to shade the circle, if you're going to draw it extending past -2, then you don't have to shade that one

Shade the circle? I don't understand. Do you mean that black spot?
yes the black spot, it was actually a circle that was shaded in. we shade the circle if we have $\geq$ or $\leq$, we leave it unshaded if we have $>$ or $<$