Solve
4^2x=2^5-x
and
9^x+1=27^2x-3
For the first one I keep getting like .4, and forthe life of me I can not figure out what im not doing right.
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Solve
4^2x=2^5-x
and
9^x+1=27^2x-3
For the first one I keep getting like .4, and forthe life of me I can not figure out what im not doing right.
I assume you mean
Note that
Now if two bases are equal then their exponents must also be equal so you get the linear equationwhich is easy to solve
For question 2 use the fact that
Thank you!