Solve

4^2x=2^5-x

and

9^x+1=27^2x-3

For the first one I keep getting like .4, and forthe life of me I can not figure out what im not doing right.

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- Dec 7th 2010, 10:54 AMabc10Exponential Equations
Solve

4^2x=2^5-x

and

9^x+1=27^2x-3

For the first one I keep getting like .4, and forthe life of me I can not figure out what im not doing right. - Dec 7th 2010, 10:57 AMe^(i*pi)
I assume you mean

Note that

Now if two bases are equal then their exponents must also be equal so you get the linear equation which is easy to solve

For question 2 use the fact that - Dec 7th 2010, 11:40 AMabc10
Thank you!