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Thread: Solve for x?

  1. December 5th 2010, 09:58 PM #1
    Klutz
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    Solve for x?

    p^2(1 − x) − 2pqx = q^2(1 + x)

    How would you make x the subject in this one?
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  2. December 5th 2010, 10:32 PM #2
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    \displaystyle p^2(1-x) - 2pq\,x = q^2(1 + x)

    \displaystyle p^2 - p^2x - 2pq\,x = q^2 + q^2x

    \displaystyle p^2 - q^2 = p^2x + 2pq\,x + q^2x

    \displaystyle p^2 - q^2 = (p^2 + 2pq + q^2)x

    \displaystyle (p-q)(p+q) = (p+q)^2x

    \displaystyle \frac{(p-q)(p+q)}{(p+q)^2} = x

    \displaystyle x = \frac{p-q}{p+q}.
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