Where is the initial 6 coming from?
Im a little confused with this problem:
A piece of cardboard is twice as long as it is wide. It is to be made into a box with an open top by cutting 3 cm squares from each corner and folding up the sides. Let x represent the width of the original piece of cardboard. Find the width of the original piece of cardboard, x, if the volume of the box is 3300 cm squared.
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I think this is how you set up the equation, but im having trouble factoring it out in the end.. so im not sure if I have it set up right.
(6)(2x-6)(x-6)= 3300
Hello, Jerry99!
The cardboard looks like this:
Code:: - - - - 2x- - - - - : - *---*-----------*---* - : |///: :///| 3 : * - *-----------* - * - : | | | | : x | | | | x-6 : | | | | : : * - *-----------* - | - : |///: :///| 3 - *---*-----------* - * - : 3 : - 2x-6 - : 3 :
The box looks like this:
Code:*-----------* /| /| / * - - - - / * / / / / *-----------* / x-6 3 | |/ *-----------* 2x-6
The volume is 3300 cm
So we have: .
. . which simplfies to: .
. . which factors: .
. . and has the positive root: .