How would I go about setting this up?
How many liters of a 30% alcohol solution must be mixed with 80 liters 0f a 90% solution to get a 40% solution ?
Thanks
Hello, Jerry99!
Here is one way to reason it out . . .
We will use liters of the 30% solution.
. . It contains: . liters of alcohol.
We have liters of the 90% solution.
. . It contains: . liters of alcohol.
The mixture will have: . liters of alcohol. .[1]
But we know that the mixture will be liters which is 40% alcohol.
. . The mixture will have: . liters of alcohol. .[2]
We just described the final amount of alcohol in two ways.
There is our equation! . . .