how is this: (4+x^2)/sqrt(4+x^2) the same as sqrt(4+x^2) ?? could someone explain step by step? thanks
Last edited by situation; Dec 2nd 2010 at 11:28 AM. Reason: fixing equation
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Originally Posted by situation how is this: (4+x^2)/sqrt(4+x^2) the same as 4+x^2 ?? could someone explain step by step? thanks Hint: for positive $\displaystyle a\in\mathbb{R}\,,\,\,\frac{a}{\sqrt{a}}=\sqrt{a}$ . Prove it! Tonio Ps. By the way, your quiestion is incorrect, of course.
If you let $\displaystyle u = \sqrt{4+x^2}$ then you get $\displaystyle \dfrac{u^2}{u}$ which is u. Alternatively, recall that $\displaystyle a = \sqrt{|a|}\sqrt{|a|}$
Originally Posted by situation how is this: (4+x^2)/sqrt(4+x^2) the same as 4+x^2 ?? could someone explain step by step? thanks do you mean $\displaystyle \dfrac{4+x^2}{\sqrt{4+x^2}}=4+x^2$?? That is not true... Actually $\displaystyle \dfrac{4+x^2}{\sqrt{4+x^2}}=\sqrt{4+x^2}$
Originally Posted by e^(i*pi) If you let $\displaystyle u = \sqrt{4+x^2}$ then you get $\displaystyle \dfrac{u^2}{u}$ which is u. Alternatively, recall that $\displaystyle a = \sqrt{|a|}\sqrt{|a|}$ god i feel stupid now! thank you
Originally Posted by harish21 do you mean $\displaystyle \dfrac{4+x^2}{\sqrt{4+x^2}}=4+x^2$?? That is not true... Actually $\displaystyle \dfrac{4+x^2}{\sqrt{4+x^2}}=\sqrt{4+x^2}$ that is what i meant sorry just couldnt see it!
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