# Thread: How to convert 50cc used in 35.55 secs to Kg/s

1. ## How to convert 50cc used in 35.55 secs to Kg/s

Hi folks,

This is my first post, and hopefully quite a simple one to start. Not sure if this is posted in the right topic area but seemed the most logical.

I'm trying to convert some numbers for a bit of thermodynamics coursework.

I've got 50cc of diesel oil that was consumed in 35.55 seconds and I need to convert that to KG/s please?? The density of the fuel is given as 0.820 (no units stated?). I assume that would be tonnes per cubic metre???

Any thoughts/help on this would be hugely appreciated.

Thanks a lot.

Jonny.

2. Originally Posted by Jonny88
Hi folks,

This is my first post, and hopefully quite a simple one to start. Not sure if this is posted in the right topic area but seemed the most logical.

I'm trying to convert some numbers for a bit of thermodynamics coursework.

I've got 50cc of diesel oil that was consumed in 35.55 seconds and I need to convert that to KG/s please?? The density of the fuel is given as 0.820 (no units stated?). I assume that would be tonnes per cubic metre???

Any thoughts/help on this would be hugely appreciated.

Thanks a lot.

Jonny.
0.820 sounds like the density in tonnes per cubic metre since IIRC crude oil is around 750kg/m^3

50cc = 50cm^3

The amount burnt in one second will be volume/time: $\dfrac{V}{t} = \dfrac{50}{35.55}$

To convert between volume and mass use the equation: $m = \rho V$

$\dfrac{m}{t} = \rho \dfrac{V}{t} \times 1000 \dfrac{\text{ kg }}{\text { tonne }}$

Plug and chug for the values given. Since I have multiplied by 1000 you can use the value of density as given in the question