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Math Help - How to convert 50cc used in 35.55 secs to Kg/s

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    Question How to convert 50cc used in 35.55 secs to Kg/s

    Hi folks,

    This is my first post, and hopefully quite a simple one to start. Not sure if this is posted in the right topic area but seemed the most logical.

    I'm trying to convert some numbers for a bit of thermodynamics coursework.

    I've got 50cc of diesel oil that was consumed in 35.55 seconds and I need to convert that to KG/s please?? The density of the fuel is given as 0.820 (no units stated?). I assume that would be tonnes per cubic metre???

    Any thoughts/help on this would be hugely appreciated.

    Thanks a lot.

    Jonny.
    Last edited by mr fantastic; December 3rd 2010 at 12:08 PM. Reason: Title.
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  2. #2
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    e^(i*pi)'s Avatar
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    Quote Originally Posted by Jonny88 View Post
    Hi folks,

    This is my first post, and hopefully quite a simple one to start. Not sure if this is posted in the right topic area but seemed the most logical.

    I'm trying to convert some numbers for a bit of thermodynamics coursework.

    I've got 50cc of diesel oil that was consumed in 35.55 seconds and I need to convert that to KG/s please?? The density of the fuel is given as 0.820 (no units stated?). I assume that would be tonnes per cubic metre???

    Any thoughts/help on this would be hugely appreciated.

    Thanks a lot.

    Jonny.
    0.820 sounds like the density in tonnes per cubic metre since IIRC crude oil is around 750kg/m^3

    50cc = 50cm^3

    The amount burnt in one second will be volume/time: \dfrac{V}{t} = \dfrac{50}{35.55}

    To convert between volume and mass use the equation: m = \rho V

    \dfrac{m}{t} = \rho \dfrac{V}{t} \times 1000 \dfrac{\text{ kg }}{\text { tonne }}

    Plug and chug for the values given. Since I have multiplied by 1000 you can use the value of density as given in the question
    Last edited by e^(i*pi); December 3rd 2010 at 01:57 AM. Reason: forgot rho in the final line
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