16x^3 -13x +3 =0 Find the real solutions for the equation. Answer : -1, 1/4, 3/4
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Originally Posted by ozacho 16x^3 -13x +3 =0 Find the real solutions for the equation. Answer : -1, 1/4, 3/4 Hi ozacho, Using the Rational Roots Theorem, you can test +/- 1 and +/- 3 as potential roots. Using synthetic division with -1, your depressed quadratic would be: $\displaystyle 16x^2-16x+3=0$ You should be able to take it from here.
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