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Thread: rationalize

  1. November 29th 2010, 09:39 AM #1
    lebanon
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    rationalize

    A=6/radical (3-radical 3)
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  2. November 29th 2010, 09:53 AM #2
    VonNemo19
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    Quote Originally Posted by lebanon View Post
    A=6/radical (3-radical 3)
    So, have you tried anything here?
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  3. November 29th 2010, 10:17 AM #3
    Archie Meade
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    Quote Originally Posted by lebanon View Post
    A=6/radical (3-radical 3)
    \displaystyle\ A=\frac{6}{\sqrt{3-\sqrt{3}}}=\sqrt{\frac{36}{3-\sqrt{3}}}=\sqrt{\frac{36(3+\sqrt{3})}{(3-\sqrt{3})(3+\sqrt{3})}


    \displaystyle\sqrt{\frac{36(3+\sqrt{3})}{9+3\sqrt{ 3}-3\sqrt{3}-3}}=\sqrt{\frac{36(3+\sqrt{3})}{9-3}}
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