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Math Help - common denominator with variables

  1. #1
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    common denominator with variables

    I am good at mathematics. However, since I stop studying pure math for about a year now, I am having trouble with a simple process to solve fraction questions. How do you get a common denominator in the following equation

    ((4x/5xy)(15y/16x^2))

    The answer is 3/4x^2 however, I cannot remember the steps needed to solve this question. It is starting to annoy me.
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  2. #2
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    No common denominator is needed with multiplication of fractions. Just times across and cancel terms where you can.
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  3. #3
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    Quote Originally Posted by pickslides View Post
    No common denominator is needed with multiplication of fractions. Just times across and cancel terms where you can.
    LOL, thank you. I was thinking about adding/subtracting them together!
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  4. #4
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    Quote Originally Posted by Barthayn View Post
    ((4x/5xy)(15y/16x^2))
    Do the multiplying:
    60xy / (80x^3 y)
    Simplify:
    3 / (4x^2)
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  5. #5
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    Quote Originally Posted by Barthayn View Post
    ((4x/5xy)(15y/16x^2)) I was thinking about adding/subtracting them together
    In this case, you should multiply the numerator and denominator of each fraction by the denominator of the other fraction and then add or subtract. So your common denominator is the product of the two denominators.
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  6. #6
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    Quote Originally Posted by Manfriedthetalkingpinata View Post
    So your common denominator is the product of the two denominators.
    As PickS said, there is NO common denominator involved...same as (1/2) * (1/4) = 1/8
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