Hi could someone please help me solve the following eqation:

4(1+r)^4-2(1+r)^2-3=0

I Know if it was a qudratic, just use the formula, but how does one solve for degree 4.

Thanks

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- Nov 27th 2010, 11:52 AM1234567Solving equation
Hi could someone please help me solve the following eqation:

4(1+r)^4-2(1+r)^2-3=0

I Know if it was a qudratic, just use the formula, but how does one solve for degree 4.

Thanks - Nov 27th 2010, 12:00 PMskeeter
- Nov 27th 2010, 12:05 PM1234567
- Nov 27th 2010, 12:06 PMArchie Meade
You could substitute

$\displaystyle x=(1+r)^2$

$\displaystyle 4x^2-2x-3=0$

Now use the quadratic formula, realising that x is a square, hence positive,

so you only need to take one solution for x.

Rearranging your solution for x will achieve the 2 solutions for r. - Nov 28th 2010, 01:46 AMHallsofIvy