Divide both sides by !
which tells us that n= 5.
With n= 5, your equation is true for all x. With n any number other than 5, it is false for all x.
I was honing my skills at a variety of previous learned math operations and found one that I was unable to solve.
125n^(x)=n^(x+3), n can not equal zero then 125n is equal to?
From checking and guessing I was able to get n=5 then confirmed that with a graphing utility. Unfortunately, I always get stuck solving 125n^(x)=n^(x+3) algebraically using logs. Could someone walk me through the steps involved to isolate the variable n
Thanks a lot.