Lr = Hx -Lx -r²x -rx² In other words how do I define x in terms of the other units: x = Thanks.
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$\displaystyle \displaystyle L\,r = H\,x - L\,x - r^2x - r\,x^2$ $\displaystyle \displaystyle L\,r = -r\,x^2 + (H - L - r^2)x$ $\displaystyle \displaystyle -L = x^2 + \left(\frac{L + r^2 - H}{r}\right)x$. Now complete the square.
x^2 + Kx + L = 0 where K = (L + r^2 - H) / r x = [-K +- sqrt(K^2 - L^2)] / 2 Isn't that good nuff?
Last edited by Wilmer; Nov 27th 2010 at 12:11 AM.
Thanks to both of you. I have forgotten all my school algebra but I will try completing the square and will get back to you if I get stuck. I am 70 and my brain doesn't work like it use to. Baz
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