1. ## Easy question

I just need to solve this with explenation, and i think that i am right and my book is wrong just want to verify

An elastic is stretched by 86% to a length of 5.8 m. Calculate the original length.
Thanks

2. Originally Posted by shanerocks
I just need to solve this with explenation, and i think that i am right and my book is wrong just want to verify

An elastic is stretched by 86% to a length of 5.8 m. Calculate the original length.
Thanks
Let the original length be $\displaystyle x$

We have $\displaystyle 1.86x = 5.8 \mbox { m }$

$\displaystyle \Rightarrow x = \frac {5.8 \mbox { m }}{1.86}$

$\displaystyle \Rightarrow x = 3.12 \mbox { m }$

3. thanks, why is it 1.86

4. Originally Posted by shanerocks
thanks, why is it 1.86
i wrote the percentage as a fraction. the original length is 100%, written as a decimal, that is 1. then we stretch it by 86%, that is, 0.86. so the new length will be 1 + 0.86 times the old length, or 1.86 times the old length, since 1.86 mean 186%

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# a piece of elastic was stretched by 24% up to a length of 31 cm. the unstretched original length of elastic is.

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