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Math Help - Finding the Equation of a quadratic function

  1. #1
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    Finding the Equation of a quadratic function

    A jet flew from tokyo to bangkok, a distance of 4800km. On the return trip, the speed was decreased by 200 km/h. If the difference in the times of the flight was 2 hours, what was the jets speed from bangkok to tokyo?
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  2. #2
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    Hello, Chr2010!

    A jet flew from Tokyo to Bangkok, a distance of 4800km.
    On the return trip, the speed was decreased by 200 km/hr.
    If the difference in the times of the flight was 2 hours,
    what was the jet's speed from Bangkok to Tokyo?

    The jet flew 4800 km from Bangkok to Tokyo at \,x km/hr.
    . . This took \dfrac{4800}{x} hours.

    The jet flew 4800 km from Tokyo to Bangkok at x  + 200 km/hr.
    . . This took \dfrac{4800}{x+200} hours.


    The difference in time was 2 hours: . \displaystyle \frac{4800}{x} - \frac{4800}{x+200} \;=\;2

    Multiply by x(x+200)\!:\;\;4800(x+200) - 4800x \;=\;2x(x+200)

    This equation simplifies to: . x^2 + 200x - 480,\!000 \:=\:0

    . . whoch factors: . (x - 600)(x + 800) \:=\:0

    . . and has roots: . x \:=\:600,\:\text{-}800


    The jet's speed from Bangkok to Tokyo was 600 km/hr.

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  3. #3
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    thanks so much!
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  4. #4
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    Hi,

    Thanks so much for your response, i understand the concept but could you walk me through on how u knew where to start and how u got the simplified equation of x^2+200x-480000. thanks
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  5. #5
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    Soroban started by choosing a letter to represent the quantity he wanted to find- in this case he let "x" represent the speed flying from Bangcock to Tokyo. You are told that the distance is 4800 km and should know that "speed= distance/time" so if we let t_2 be the time the flight took, x= \frac{4800}{t_2} so, solving that for t_2, t_2= \frac{4800}{x}.

    We don't know t_2 so we can use that equation alone to find x. But we also know that "On the return trip, the speed was decreased by 200 km/h". Since is the speed on the return trip, the speed on the first leg must be 200 more: x+ 200. The time to fly the same 4800 is t_1= \frac{4800}{x+ 200}. That flight was at a faster speed so of course, it takes less time- 2 hours less: t_2- t_1, the difference in times, is 2 hours:
    t_2- t_1= \frac{4800}{x}- \frac{4800}{x+ 200}= 2

    Get rid of the fractions by multiplying both sides of that equation by x(x+ 200) and you get the quadratic equation Soroban gave.
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  6. #6
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    thank-you!
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