Hi,

I'm not getting this. I'm wrong - as usual. May I have some help please?

If $\displaystyle 3(27)^x = 9^{2x\,+\,1}$, what is the value of x?

$\displaystyle 81^x = 9^{2x\,+\,1}$

$\displaystyle x \log 81 = (2x + 1) \log 9$

$\displaystyle x \log 81 = 2x \log 9 + \log 9$

$\displaystyle x \log 81 - 2x \log 9 = \log 9$

$\displaystyle x(\log 81 - 2 \log 9) = \log 9$

$\displaystyle x = \frac{\log 9}{\log 81 - 2 \log 9}$

x = Undefined