9/x-5 + 3/x = -15/x^2-5x

First thing I do is find the LCD which i think is x(x-5) or x^2-5x

I eventually get the equation down to 9x+3x-15=-15

at this point I want to say x=0, but knowing that I can take this further im kind of tempted to(and im kind of second guessing myself), and very stuck in the process. If x=0 then there would be "no solution", correct?

i factor a 3 out: 3(2x+x-5)=-15

and this is where im stuck.

thanks for any help given