hi i need to know how to draw, Y=3x-1 on a graph!

im not too sure but would it look like this:

Attachment 19818

if not could you please point my in the right direction! but if it is correct could you also let me know!

thanks!

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- Nov 23rd 2010, 08:14 AMandyboy179draw
hi i need to know how to draw, Y=3x-1 on a graph!

im not too sure but would it look like this:

Attachment 19818

if not could you please point my in the right direction! but if it is correct could you also let me know!

thanks! - Nov 23rd 2010, 08:43 AMChris L T521
You're rather close with your graph...however, the line you drew has slope $\displaystyle m=\frac{1}{3}$.

To get the correct graph, start with the point (0,-1) [the y intercept]. Now since the slope of the line is $\displaystyle m=\dfrac{\text{rise}}{\text{run}}=\dfrac{3}{1}$, go up 3 units from the y intercept, and then move 1 unit to the right to get the next point (1,2). Then connect the two points and that's your line.

Does this make sense? - Nov 23rd 2010, 08:48 AMandyboy179
so it would be:

Attachment 19819 - Nov 23rd 2010, 08:49 AMChris L T521
- Nov 23rd 2010, 08:54 AMandyboy179
what if the question was 2x=y=7 would it look like this:

Attachment 19820 - Nov 23rd 2010, 09:03 AMChris L T521
Do you mean 2x+y=7? If so, you're close...your x intercept isn't correct, but it has the right orientation.

So...to get the correct x intercept, what is the value of x in the equation if y=0?

Also, in the future, please make new threads for new questions -- it makes it easier for the other users to follow what's going on. - Nov 23rd 2010, 09:30 AMandyboy179
ok sorry!

would i be:

Attachment 19821