# draw

• Nov 23rd 2010, 08:14 AM
andyboy179
draw
hi i need to know how to draw, Y=3x-1 on a graph!
im not too sure but would it look like this:
Attachment 19818

if not could you please point my in the right direction! but if it is correct could you also let me know!

thanks!
• Nov 23rd 2010, 08:43 AM
Chris L T521
Quote:

Originally Posted by andyboy179
hi i need to know how to draw, Y=3x-1 on a graph!
im not too sure but would it look like this:
Attachment 19818

if not could you please point my in the right direction! but if it is correct could you also let me know!

thanks!

You're rather close with your graph...however, the line you drew has slope $m=\frac{1}{3}$.

To get the correct graph, start with the point (0,-1) [the y intercept]. Now since the slope of the line is $m=\dfrac{\text{rise}}{\text{run}}=\dfrac{3}{1}$, go up 3 units from the y intercept, and then move 1 unit to the right to get the next point (1,2). Then connect the two points and that's your line.

Does this make sense?
• Nov 23rd 2010, 08:48 AM
andyboy179
so it would be:
Attachment 19819
• Nov 23rd 2010, 08:49 AM
Chris L T521
Quote:

Originally Posted by andyboy179
so it would be:
Attachment 19819

Good job. (Yes)
• Nov 23rd 2010, 08:54 AM
andyboy179
what if the question was 2x=y=7 would it look like this:
Attachment 19820
• Nov 23rd 2010, 09:03 AM
Chris L T521
Quote:

Originally Posted by andyboy179
what if the question was 2x=y=7 would it look like this:
Attachment 19820

Do you mean 2x+y=7? If so, you're close...your x intercept isn't correct, but it has the right orientation.

So...to get the correct x intercept, what is the value of x in the equation if y=0?

Also, in the future, please make new threads for new questions -- it makes it easier for the other users to follow what's going on.
• Nov 23rd 2010, 09:30 AM
andyboy179
ok sorry!

would i be:
Attachment 19821