Hello, andyboy179!
There is no factoring in this problem.
I assume we have some quadrilateral and those expressions are the four angles.
Since the angles of a quadrilateral always total $\displaystyle 360^o$
. . . . your work is correct: .$\displaystyle 7x\:=\:360 ^o\quad\Rightarrow\quad x \:=\:\dfrac{360^o}{7} \:=\:51\frac{3}{7}^o$
Then the four angles are:
. . $\displaystyle \begin{array}{cccc}3x-1 \:=\:153\frac{2}{7}^o && x+2 \:=\:53\frac{3}{7}^o \\ \\ x-4 \:=\:47\frac{3}{7}^o && 2x+3 \:=\:105\frac{6}{7}^o \end{array}$