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Math Help - rearranging formula

  1. #1
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    rearranging formula

    (z+h)+[(Q/b*(z+h))^2/(2*g)]=z

    Could someone please solve for z.

    We know all the variables apart from z.

    Cheers
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  2. #2
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    Well, this is the best I can make out from how you have the original problem written... learning to write this stuff in TEX on here can be helpful

    z+h+\frac{(\frac{Q}{b}(z+h))^2}{2g}=z.

    Is this the correct problem?

    Btw, I don't think this belongs in this section... this really feels like more of a basic algebra question than abstract algebra or whatever.

    But I'll help anyway since it's here.

    What work have you been able to do yourself so far?
    Last edited by topspin1617; November 22nd 2010 at 06:50 PM.
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  3. #3
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    Quote Originally Posted by Haris View Post
    (z+h)+[(Q/b*(z+h))^2/(2*g)]=z

    Could someone please solve for z.

    We know all the variables apart from z.

    Cheers
    If you introduce some new notation such as x = z + h and (Q/b)^2/2g = a it's much easier to see:

    x + ax^2 = x - h \Rightarrow ax^2 = -h. If a < 0 then there is no real solution for x and hence z.
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