If $\displaystyle

2^x4^y = 32

$

and $\displaystyle

\frac{3^x}{9^y}=3

$

then $\displaystyle

\frac{5^x}{125^y}= ?

$

This time the answer is $\displaystyle 1$

I was trying to use the Logarithmic Properties to solve it, but I wasn't getting the correct answer.

How should I solve this?

Thanks in advance.