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Math Help - hey everybody i have one more PLEASE HELP

  1. #1
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    Talking hey everybody i have one more PLEASE HELP

    if the sides of a square are decreased by 2 cm, the area is decreased by 36cm^2, what were the dimensions of the original square.

    im thinking that dimension is the sides

    a=s^2 right? i forget the formulas.

    sides = x-2

    area= x-36cm^2

    if this is right so far can you help me from here or correct what i have and explain. thanks

    Last edited by CaptainBlack; June 28th 2007 at 03:31 PM.
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  2. #2
    Eater of Worlds
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    You have the original square: A=x^{2}

    decrease the sides by 2 and the area decreases by 36:

    (x-2)^{2}=A-36

    From the first equation x=\sqrt{A}

    Then we have:

    (\sqrt{A}-2)^{2}=A-36

    A-4\sqrt{A}+4=A-36

    A-4\sqrt{A}=A-40

    \sqrt{A}=10

    A=100
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