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Math Help - I canīt solve this situation =S (algebra II)

  1. #1
    Newbie PxEckx's Avatar
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    Question I canīt solve this situation =S (algebra II)

    Hello folks =)

    This is a 'situation' that looks so simple to solve, but I don't realy know how to star it!

    Here cames:


    'A man bought product A, by US$ 96, and product B, by US$ 84. Know that: the total os products bought was 26, and the price of one product A is US$ 2 more expensive than one product B. How many product A were bought?'



    Can somebody, please, help me???


    PS: I tried to make a system, using x = product A and y = product B, but than I get lost with the prices..... =(
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  2. #2
    Newbie PxEckx's Avatar
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    Ahn

    Can I do something like

    A = B + 2 ?
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  3. #3
    MHF Contributor
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    Price of each A = a ; then price of each B = a-2
    Number of A's = n ; then number of B's = 26 - n

    an = 96
    (a-2)(26-n) = 84

    I'll leave you the pleasure of finishing it!
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