# hi everyone, i have an assignment due and i really need help

• Jun 28th 2007, 01:41 PM
beautiful
hi everyone, i have an assignment due and i really need help
i'm stuck on this problem.
i used the ac theory like this

14x^2 -20x +6

a=14 b= -20 c=6

ac=14(6)=48
b= -20

there are no two numbers that will multiply together and get 48 and at the same time be added together to get -20

i also tried to just factor by using 2 to get 7x^2 - 10x +3 and i ran into the same problem.

• Jun 28th 2007, 02:23 PM
CaptainBlack
Quote:

Originally Posted by beautiful
i'm stuck on this problem.
i used the ac theory like this

14x^2 -20x +6

a=14 b= -20 c=6

ac=14(6)=48
b= -20

there are no two numbers that will multiply together and get 48 and at the same time be added together to get -20

i also tried to just factor by using 2 to get 7x^2 - 10x +3 and i ran into the same problem.

7x^2 - 10x +3 = (x - 1)(7x - 3)

RonL
• Jun 29th 2007, 06:39 AM
earboth
Quote:

Originally Posted by beautiful
...
ac=14(6)=48
b= -20

Hello,

maybe this helps a little bit further:

a*c = 14*6 = 84
• Jun 29th 2007, 07:49 AM
Soroban
Hello, beautiful!

Quote:

i'm stuck on this problem.

i used the $\displaystyle ac$ theory like this: .$\displaystyle 14x^2 -20x +6$

. . $\displaystyle a=14,\:b= -20,\:c=6$

. . $\displaystyle ac\:=\:14(6)\:=\:48$ . . Here! . 14 × 6 = 84

• Jun 29th 2007, 07:53 AM
Krizalid
Quote:

Originally Posted by beautiful
$\displaystyle 14x^2-20x+6$

\displaystyle \begin{aligned}14x^2-20x+6&=14x^2-(14x+6x)+6\\&=(14x^2-14x)-(6x-6)\\&=(x-1)(14x-6)\end{aligned}