My problem says : Factor each polynomial: x^2+2xy+y^2
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Originally Posted by mrking My problem says : Factor each polynomial: x^2+2xy+y^2 $\displaystyle (x+y)(x+y)$
can you show the work please because I have 3 or 4 more almost exactly like this
Originally Posted by mrking can you show the work please because I have 3 or 4 more almost exactly like this this is a basic factorization ... you're expected to be familiar with the pattern $\displaystyle (a+b)^2 = a^2 + 2ab + b^2$
the only equation that my teacher has given me is x^2+bx+c=0. Is this similar?
Originally Posted by mrking the only equation that my teacher has given me is x^2+bx+c=0. Is this similar? go to the link ... Factoring Quadratics: The Simple Case
I have another problem that says: a^2+4ab+4b^2 The solution that I came to is: (a-2b)(a-2b) is this correct?
As skeeter has shown $\displaystyle (x+y)^2 = x^2+2xy+y^2$ and $\displaystyle (x-y)^2 = x^2-2xy+y^2$ In your case $\displaystyle a^2+4ab+4b^2 = a^2+2\times2ab+(2b)^2 = (a+2b)(a+2b) = (a+2b)^2$
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