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Math Help - assistance please

  1. #16
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    sustittbe k = -0.501359133
    and t = 5

    and solve for U

    is that it
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  2. #17
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    Sounds good to me. What do you get?
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  3. #18
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    <br />
U = 20 + (11 - 20)e^{(5)(-0.50)}<br />
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  4. #19
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    Uh-huh. And the result is?
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  5. #20
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    <br />
U = 20 + (11 - 20)e^{-2.5}<br />

    <br />
U = 20 + (11 - 20)e^{-2.5}<br />

    <br />
U = 20 + (-9)0.0820<br />

    <br />
U = 20 + -0.738<br />

    <br />
U = 19.26200<br />

    is this it
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  6. #21
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    Looks good to me.
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  7. #22
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    And it makes sense, because it's a value closer to room temperature than the value you read off at 3 minutes. That is what you'd expect, right?
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