# Simultaneous equations help

• Nov 15th 2010, 10:28 PM
jgv115
Simultaneous equations help
A barbecue manufacturer makes 2 models, the Outback and Bush Walker. It is known that 20 percent more of the Outback model is sold than the Bush Walker. A profit of \$200 is made on each Outback sold but \$350 is made on each Bush Walker. If during the next year a profit of \$177000 is planned, how many of each barbecue must be sold?

How would I go about doing this? I've already tried but I can't seem to get a start. Can someone start me off?

All I have atm is

Let a be the total number of Outbacks sold and b is Bushwalkers sold

$200a+350b = 177000$

Well I figured some more out. Since there is 20 percent more of $a$ sold than $b$ that means $b=0.8a$

If I sub that in I get a=368.75 and b=295

Is this right?
• Nov 15th 2010, 11:27 PM
Prove It
Actually, if 20% more of the ouback model is sold than the bushwalker, then $\displaystyle a = 1.2 b$ (because you end up with 120% of the number of bushwalkers).

So substitute this into your other equation.
• Nov 17th 2010, 03:41 AM
jgv115
Thanks Prove It.

Appreciated bro :)