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Math Help - Does this simplify?

  1. #1
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    Does this simplify?

    N= \frac {-2 + \frac {1}{1-W} }{2-\frac {1}{W}} - \frac {L}{P(2-\frac {1}{W}) }
    I was wondering if this could be simplified. W ranges from 0 to 1, P, L, and N are all positive. I'd also like to create a table or a graph of N in terms of P, L or W, given we know the other 2 but I don't know how to do that in MatLab, any tips?.
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  2. #2
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    You can remove the fractions...

    \dfrac{\frac{-2(1-W) + 1}{1-W}}{\frac{2W-1}{W}} - \dfrac{L}{2P - \frac{P}{W}}

    \dfrac{\frac{-2+2W + 1}{1-W}}{\frac{2W-1}{W}} - \dfrac{LW}{2PW - P}

    \dfrac{\frac{2W -1}{1-W}}{\frac{2W-1}{W}} - \dfrac{LW}{2PW - P}

    \dfrac{W}{1-W} - \dfrac{LW}{P(2W -1)}

    This should be ok.
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  3. #3
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    Quote Originally Posted by frankdent1 View Post
    N= \frac {-2 + \frac {1}{1-W} }{2-\frac {1}{W}} - \frac {L}{P(2-\frac {1}{W}) }
    I was wondering if this could be simplified. W ranges from 0 to 1, P, L, and N are all positive. I'd also like to create a table or a graph of N in terms of P, L or W, given we know the other 2 but I don't know how to do that in MatLab, any tips?.
    > W ranges from 0 to 1.....
    W cannot equal 0, 1 or .5 since each of these will create a division by 0

    > P, L, and N are all positive.
    N is negative in many cases; as example, if W = .8, L = 15 and P = 2, then N = -6.
    So if you want only cases where N > 0, then you need a condition in your program.

    > I was wondering if this could be simplified
    WHY do you want/need it simplified?
    From what I can see, you're calculating N through some program; like:
    Get W,L,P
    Calculate N (using your given formula)
    If what you mean is in order to "reduce" the physical size of the formula,
    then you'd be better off with stuff like:
    let A = 1/(1 - W) and B = 2 - 1/W ; then formula becomes:
    N = (A - 2) / B - L / (PB)
    Get my drift?
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  4. #4
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    Thanks for the answer. It's a bit complicated, I'm using this formula for poker and wanted to simplify it in order to do better calculations in my head. Here W is a percent, that's why I said 0 to 1, what I should have said was a percent 0<W<0.5 , which should make N always positive, N is also a percentage but it can go over 100% and there's no real cap to it. P and L are pot and stack sizes. Thanks for the tip on reducing the physical size of the formula, It could make graphing it easier. I could set certain values as known like P, L and graph N in terms of W or switch them around and graph in terms of P or L.
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