A complex problem on number

**Dexterkannan** · November 14th 2010, 04:06 AM

Dear All ,

Q> When the numerator of a fraction increases by 4 ,the fraction increases by
2/3.The denominator of the fraction is ???

Ans > 6

but my doubt is in the solution:

let Fraction be - x/y.
then (x+4)/y - x/y = 2/3

ie y = 6

but why -x/y

pls explain me the solution pls

**Prove It** · November 14th 2010, 04:10 AM

LHS: Numerator of the fraction increases by $\displaystyle 4$ , so $\displaystyle \frac{x + 4}{y}$ .

RHS: Fraction increases by $\displaystyle \frac{2}{3}$ , so $\displaystyle \frac{x}{y} + \frac{2}{3}$ .

Therefore

$\displaystyle \frac{x + 4}{y} = \frac{x}{y} + \frac{2}{3}$

$\displaystyle \frac{x + 4}{y} - \frac{x}{y} = \frac{2}{3}$

$\displaystyle \frac{x + 4 - x}{y} = \frac{2}{3}$

$\displaystyle \frac{4}{y} = \frac{2}{3}$ .

Since $\displaystyle \frac{4}{6} = \frac{2}{3}$ , that means $\displaystyle y=6$ .

**Dexterkannan** · November 14th 2010, 04:22 AM

Thankx ,solution is crystal clear sir...
Thankx a lot

DexKann

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