If ln a = 2, ln b = 3, and ln c = 5, evaluate: 1. ln((a^-4)(b^1)) / ln(bc)^3 and 2. (ln c^-1)(ln a/(b^3))^4
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Recall and apply your log rules. log (AB) = log A + log B log(A/B) = log A - log B log (A)^n = n logA
In the following lines, I mean to say ln(a^-4), not ln(a-4). Latex issues, sorry.
Originally Posted by rtblue In the following lines, I mean to say ln(a^-4), not ln(a-4). Latex issues, sorry. FYI you can use [tex]\ln \left(a^{-4}\right)[/tex] which gives I've nothing new to contribute to the thread, look at the two posts above me
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