2*x ^2 - 13*x + 18 = 0

So far I get :

General Term : a*x^2 + b*x + c

Which would be factored into :

(m*x + p) * ( n*x + q)

Where

m*n = a

p*q = c and

P*n + m*q = b

Step 1 -

m*n = 2

p*q = 18

P*n + m*q = -13

Step 2 -

Possible integer multiples

m n (and obverse)

2 = 1 & 2

Possible integer multiples

p q (and obverse)

18 = 1 & 18

2 & 9

3 & 6

So I get

(2*x + p)*(x + q) now I think I get a - 13 and an 18 so lets try

(2*x - 3) * (x - 6)

I now get lost help anyone. ...