i don't know what i would do from here so could someone please explain how to do this please?
not sure but would i times the 2 brackets to make, x^2 + x -2?
November 12th 2010, 06:06 AM
I think you should be more careful with parentheses. Do you mean x-(1/2) or, as I suspect, (x-1)/2? There are too many ambiguities here for me to parse what you mean. Can you add some parentheses, please?
November 12th 2010, 06:14 AM
oh sorry, im not too good with posting with all the codes!
for x. Is that correct? If so, the first thing you're going to need to do is get a common denominator on the LHS. What is the common denominator?
November 12th 2010, 06:20 AM
im not too sure how i would find that. would i be 1
November 12th 2010, 06:22 AM
It's the "least common multiple" of the denominators. But you have to view things like x+2 as a single factor. So what do you think?
November 12th 2010, 06:26 AM
im still not sure. would x+2? or 2?
November 12th 2010, 06:27 AM
What's the least common multiple of 2 and 3?
November 12th 2010, 06:29 AM
November 12th 2010, 06:30 AM
So what's the LCM of 4 and 6?
November 12th 2010, 06:32 AM
12, one question, i don't understand why we need to find the LCM?
November 12th 2010, 06:35 AM
Correct. I'm trying to help you with an analogy. Finding the common denominator is THE SAME as finding the least common multiple of the denominators. And it works the same way for factors like x+2 as it does for numbers. So, what is the common denominator for your two fractions? (Your answer in post # 7 is incorrect, but you're on the right track.)
November 12th 2010, 06:37 AM
oh okay! i know the LCM between 2 and 2 is 2 but i get confused when the x comes in!
November 12th 2010, 06:42 AM
You're not the only one who gets confused by this, trust me. Think of x+2 as (x+2). That is, when you compute the LCM of (2) and (3), you viewed (2) as a "factor" and (3) as a "factor". With these two denominators, you have to view (2) as a factor and (x+2) as a factor. Does that help? If so, what do you think is the common denominator?