# Math Help - sove:(ax+b)/(cx+d) predigest this multinomial

1. ## sove:(ax+b)/(cx+d) predigest this multinomial

but i couldn't solve the process.
can you give me the detailed process?
thank u

2. Originally Posted by neworld222
but i couldn't solve the process.
can you give me the detailed process?
thank u
It would appear the "predigestion" is long division?

I'll give you a hint: how do you do the long division for the numbers 71/23?

-Dan

3. Originally Posted by topsquark
It would appear the "predigestion" is long division?

I'll give you a hint: how do you do the long division for the numbers 71/23?

-Dan
yes ,my question is ,i don't know the progress how (ax+b)/(cx+d) to a/c+[(bc-ad)/c^2]*1/(x+d/c)
could you give this grogress?

4. Originally Posted by neworld222
yes ,my question is ,i don't know the progress how (ax+b)/(cx+d) to a/c+[(bc-ad)/c^2]*1/(x+d/c)
could you give this grogress?
The short answer is "no." Simply because I hate typing in that "code" box. But I can provide you with a link (which process should be in your text anyway) that shows you the process.

The first step (which is not commonly taken in most problems) in your problem is this:
$\frac{ax + b}{cx + d} = \frac{ax + b}{c \left ( x + \frac{d}{c} \right ) }$

$= \frac{ \frac{1}{c} (ax + b)}{x + \frac{d}{c}}$

$= \frac{\left ( \frac{a}{c} \right ) x + \frac{b}{c}}{x + \frac{d}{c}}$

-Dan

5. Originally Posted by topsquark
The short answer is "no." Simply because I hate typing in that "code" box. But I can provide you with a link (which process should be in your text anyway) that shows you the process.

The first step (which is not commonly taken in most problems) in your problem is this:
$\frac{ax + b}{cx + d} = \frac{ax + b}{c \left ( x + \frac{d}{c} \right ) }$

$= \frac{ \frac{1}{c} (ax + b)}{x + \frac{d}{c}}$

$= \frac{\left ( \frac{a}{c} \right ) x + \frac{b}{c}}{x + \frac{d}{c}}$