the answer is a/c+[(bc-ad)/c^2]*1/(x+d/c)

but i couldn't solve the process.

can you give me the detailed process?

thank u:)

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- Jun 26th 2007, 06:38 AMneworld222sove:(ax+b)/(cx+d) predigest this multinomial
the answer is a/c+[(bc-ad)/c^2]*1/(x+d/c)

but i couldn't solve the process.

can you give me the detailed process?

thank u:)

- Jun 26th 2007, 07:08 AMtopsquark
- Jun 26th 2007, 07:13 AMneworld222
- Jun 26th 2007, 07:39 AMtopsquark
The short answer is "no." Simply because I hate typing in that "code" box. But I can provide you with a link (which process should be in your text anyway) that shows you the process.

The first step (which is not commonly taken in most problems) in your problem is this:

$\displaystyle \frac{ax + b}{cx + d} = \frac{ax + b}{c \left ( x + \frac{d}{c} \right ) }$

$\displaystyle = \frac{ \frac{1}{c} (ax + b)}{x + \frac{d}{c}}$

$\displaystyle = \frac{\left ( \frac{a}{c} \right ) x + \frac{b}{c}}{x + \frac{d}{c}}$

Now do your long division.

-Dan - Jun 26th 2007, 10:25 AMneworld222
thx ,i have done my long division by your manner you told me. thx a lot,i'm not a english said man,so my english is so bad:)

tha map below is what i have done by 'MathType'

Attachment 3414