# sove:(ax+b)/(cx+d) predigest this multinomial

• Jun 26th 2007, 06:38 AM
neworld222
sove:(ax+b)/(cx+d) predigest this multinomial
but i couldn't solve the process.
can you give me the detailed process?
thank u:)
• Jun 26th 2007, 07:08 AM
topsquark
Quote:

Originally Posted by neworld222
but i couldn't solve the process.
can you give me the detailed process?
thank u:)

It would appear the "predigestion" is long division?

I'll give you a hint: how do you do the long division for the numbers 71/23?

-Dan
• Jun 26th 2007, 07:13 AM
neworld222
Quote:

Originally Posted by topsquark
It would appear the "predigestion" is long division?

I'll give you a hint: how do you do the long division for the numbers 71/23?

-Dan

yes ,my question is ,i don't know the progress how (ax+b)/(cx+d) to a/c+[(bc-ad)/c^2]*1/(x+d/c)
could you give this grogress?
• Jun 26th 2007, 07:39 AM
topsquark
Quote:

Originally Posted by neworld222
yes ,my question is ,i don't know the progress how (ax+b)/(cx+d) to a/c+[(bc-ad)/c^2]*1/(x+d/c)
could you give this grogress?

The short answer is "no." Simply because I hate typing in that "code" box. But I can provide you with a link (which process should be in your text anyway) that shows you the process.

The first step (which is not commonly taken in most problems) in your problem is this:
$\displaystyle \frac{ax + b}{cx + d} = \frac{ax + b}{c \left ( x + \frac{d}{c} \right ) }$

$\displaystyle = \frac{ \frac{1}{c} (ax + b)}{x + \frac{d}{c}}$

$\displaystyle = \frac{\left ( \frac{a}{c} \right ) x + \frac{b}{c}}{x + \frac{d}{c}}$

-Dan
• Jun 26th 2007, 10:25 AM
neworld222
Quote:

Originally Posted by topsquark
The short answer is "no." Simply because I hate typing in that "code" box. But I can provide you with a link (which process should be in your text anyway) that shows you the process.

The first step (which is not commonly taken in most problems) in your problem is this:
$\displaystyle \frac{ax + b}{cx + d} = \frac{ax + b}{c \left ( x + \frac{d}{c} \right ) }$

$\displaystyle = \frac{ \frac{1}{c} (ax + b)}{x + \frac{d}{c}}$

$\displaystyle = \frac{\left ( \frac{a}{c} \right ) x + \frac{b}{c}}{x + \frac{d}{c}}$