Hi Guys

Im stuck on the following question

3x^2+16x-12=0 hence solve 3(y-(7/y))^(2)+16(y-(7/y))-12=0

I can get the factors (3x-2) and (x+6) for the first one and so x=2/3 x= -6

its the second part im stuck on

any help would be great please

Thanks

Pete