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Math Help - System of Equations

  1. #1
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    System of Equations

    I should really know how to solve this seeing as I will be taking Cal II next semester...so this is kind of embarrassing, but I just keep getting stuck for some reason.

    \frac{-5}{4}=\frac{29}{4}+c+d

    404=432+4c+d

    Here is what I have until the point where I get stuck...

    \frac{-5}{4}*\frac{4}{1}=\frac{4}{1}*(\frac{29}{4}+c+d)

    -5=29+4c+4d

    \frac{-34}{4d}=4c

    404=432+4c+d

    -28=4c+d

    -28=\frac{-34}{4d}+d

    Here is where I start getting myself all messed up, any hints on what step to take next?
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  2. #2
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    Why don't you just subtract the first equation from the second to eliminate \displaystyle d?
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  3. #3
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    Quote Originally Posted by dbakeg00 View Post
    \frac{-5}{4}=\frac{29}{4}+c+d ...(1)

    404=432+4c+d ...(2)
    I get,

    (2)-(1) = 404-\frac{-5}{4}=432-\frac{29}{4}+3c

    = \frac{1616}{4}-\frac{-5}{4}=\frac{1728}{4}-\frac{29}{4}+3c

    = \frac{1621}{4}=\frac{1699}{4}+3c

    = \frac{-78}{4}=3c

    = -6.5=c
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  4. #4
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    I should have seen that!! Thanks

    I ended up getting c=\frac{-13}{2} and d=-2

    Appreciate the help!
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