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• Jun 25th 2007, 07:22 PM
Sazza
A Syndicate of two people wins a lottery prize of $25 000, to be shared in the ratio of 3:2, Find the Larger Share. Show appropriate working. If a Steel Bar 90 cm long weighs 3.6 kg, find the weight of a similar length of 1.5 m. A Long haul truckie knows that his truck uses 153 litres of fuel for a trip of 850 km. How much fuel must he carry for a trip of 1350 km? How do i find these out? • Jun 25th 2007, 07:45 PM Jonboy Hi Sazza! That neon green font is kinda tough to read... Quote: Originally Posted by Sazza 1) A Syndicate of two people wins a lottery prize of$25 000, to be shared in the ratio of 3:2, Find the Larger Share. Show appropriate working.

See Jhevon's brilliant explanation. :)

Quote:

2) If a Steel Bar 90 cm long weighs 3.6 kg, find the weight of a similar length of 1.5 m.

Have you heard of proportions? A comparison of two ratios?

We've got to have like units. One 1 m = 100 cm. So the 1.5 m = 150 cm.

Just solve for x:... $\frac{90}{3.6}\,=\,\frac{150}{x}$

Quote:

3) A Long haul truckie knows that his truck uses 153 litres of fuel for a trip of 850 km. How much fuel must he carry for a trip of 1350 km?

Make a proportion.

You should get:
.. $\frac{153}{850}\,=\,\frac{x}{1350}$
• Jun 25th 2007, 08:01 PM
Jhevon
Hello Sazza,

I second what Jonboy said about the neon green font. That's downright painful to read, especially since i've been around my pc all day

Quote:

Originally Posted by Sazza
A Syndicate of two people wins a lottery prize of \$25 000, to be shared in the ratio of 3:2, Find the Larger Share. Show appropriate working.

Quote:

Originally Posted by Jonboy

Since you have the ratio 3:2, to find the larger sum:.. $25,000\,\cdot\,3\,=\, 75,000$

Um, i'm sorry, but that's not correct. A ratio of 3:2 means that 3 parts goes to one person and 2 parts goes to the other. there are a total of 5 parts. so one person gets 3/5 of the winnings, and the other gets 2/5 of the winnings.

Thus the larger portion is: $\frac {3}{5} \cdot 25000 = 15000$

How could the larger share be greater than the entire amount?
• Jun 25th 2007, 08:05 PM
Jonboy
Quote:

Originally Posted by Jhevon

How could the larger share be greater than the entire amount?

LOL sorry about that. I originally thought what you thought but then I went the wrong way. Thanks for clearing that up. :D
• Jun 25th 2007, 08:17 PM
Sazza
• Jun 25th 2007, 08:20 PM
Jhevon
Quote:

Originally Posted by Sazza

yup, all your love and happiness is too much for us!

just kidding, it's fine. just try to be happy and lovely in a more optically-friendly way :D
• Jun 25th 2007, 08:49 PM
Sazza
haha yup =]
• Jun 26th 2007, 11:13 PM
Sazza
Quote: Have you heard of proportions? A comparison of two ratios?

We've got to have like units. One 1 m = 100 cm. So the 1.5 m = 150 cm.

Just solve for x:...
http://www.mathhelpforum.com/math-he...1713a3c5-1.gif

Does that mean the if i find the value of x, than i'm finding the amount? :confused:
90 divided by 3.6 x 150 = 3,790??
• Jun 26th 2007, 11:24 PM
topsquark
Quote:

Originally Posted by Sazza
Quote: Have you heard of proportions? A comparison of two ratios?

We've got to have like units. One 1 m = 100 cm. So the 1.5 m = 150 cm.

Just solve for x:...
http://www.mathhelpforum.com/math-he...1713a3c5-1.gif

Does that mean the if i find the value of x, than i'm finding the amount? :confused:
90 divided by 3.6 x 150 = 3,790??

Yes, if you find x you are finding the amount.

No to " 90 divided by 3.6 x 150 = 3,790"

$\frac{90}{3.6} = \frac{150}{x}$

To get rid of the fractions, multiply both sides by 3.6x, or just simply "cross multiply":

$90x = 150 \cdot 3.6 = 540$

$x = \frac{540}{90}$

$x = 6$

-Dan
• Jun 27th 2007, 05:45 PM
Sazza
Quote:

Originally Posted by Jonboy
Just solve for x:... $\frac{90}{3.6}\,=\,\frac{150}{x}$

Make a proportion.

You should get:.. $\frac{153}{850}\,=\,\frac{x}{1350}$

so it would be: 153 divided by 850 x 1350 = 243??
• Jun 27th 2007, 05:49 PM
Jhevon
Quote:

Originally Posted by Sazza
so it would be: 153 divided by 850 x 1350 = 243??

yes
• Jun 27th 2007, 07:06 PM
Sazza
Okay thanks =] and i've been flipping through my mathematic books, because my teacher has hinted that they'll be asking about variables as in: 2a + 3a
so i thought i'd do some revision! Is a the coefficient of 2? i can't remember the name! :eek:
• Jun 27th 2007, 07:12 PM
Sazza
rightio =] thanks, i'll be going to my exam now. My doom :eek: haha nah! Well i haven't memoried all the angles like isosolece, or revolution but i'll do my best! Wish me luck :rolleyes:
• Jun 27th 2007, 07:16 PM
Jonboy
Quote:

Originally Posted by Sazza
rightio =] thanks, i'll be going to my exam now. My doom :eek: haha nah! Well i haven't memoried all the angles like isosolece, or revolution but i'll do my best! Wish me luck :rolleyes:

Haha. Hey, I know you can do it. Just some comprehensive studying and use logic then I'm sure you'll do fine. :cool:
• Jun 27th 2007, 07:26 PM
Jhevon
the coefficient is the number that accompanies the variable, conventionally written in front of the variable.

so for 2a + 3a

the variable is a

the coefficients are 2 and 3

Good Luck!
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