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June 25th 2007, 06:22 PM
Sazza

Help Please

A Syndicate of two people wins a lottery prize of $25 000, to be shared in the ratio of 3:2, Find the Larger Share. Show appropriate working.

If a Steel Bar 90 cm long weighs 3.6 kg, find the weight of a similar length of 1.5 m.

A Long haul truckie knows that his truck uses 153 litres of fuel for a trip of 850 km. How much fuel must he carry for a trip of 1350 km?

How do i find these out?
June 25th 2007, 06:45 PM
Jonboy

Hi Sazza! That neon green font is kinda tough to read...

Quote:

Originally Posted by Sazza

1) A Syndicate of two people wins a lottery prize of $25 000, to be shared in the ratio of 3:2, Find the Larger Share. Show appropriate working.

See Jhevon's brilliant explanation. :)

Quote:

2) If a Steel Bar 90 cm long weighs 3.6 kg, find the weight of a similar length of 1.5 m.

Have you heard of proportions? A comparison of two ratios?

We've got to have like units. One 1 m = 100 cm. So the 1.5 m = 150 cm.

Just solve for x:... $\frac{90}{3.6}\,=\,\frac{150}{x}$

Quote:

3) A Long haul truckie knows that his truck uses 153 litres of fuel for a trip of 850 km. How much fuel must he carry for a trip of 1350 km?

Make a proportion.

You should get:.. $\frac{153}{850}\,=\,\frac{x}{1350}$
June 25th 2007, 07:01 PM
Jhevon

Hello Sazza,

I second what Jonboy said about the neon green font. That's downright painful to read, especially since i've been around my pc all day

Quote:

Originally Posted by Sazza

A Syndicate of two people wins a lottery prize of $25 000, to be shared in the ratio of 3:2, Find the Larger Share. Show appropriate working.

Quote:

Originally Posted by Jonboy

Since you have the ratio 3:2, to find the larger sum:.. $25,000\,\cdot\,3\,=\, 75,000$

Um, i'm sorry, but that's not correct. A ratio of 3:2 means that 3 parts goes to one person and 2 parts goes to the other. there are a total of 5 parts. so one person gets 3/5 of the winnings, and the other gets 2/5 of the winnings.

Thus the larger portion is: $\frac {3}{5} \cdot 25000 = 15000$

How could the larger share be greater than the entire amount?
June 25th 2007, 07:05 PM
Jonboy

Quote:

Originally Posted by Jhevon

How could the larger share be greater than the entire amount?

LOL sorry about that. I originally thought what you thought but then I went the wrong way. Thanks for clearing that up. :D
June 25th 2007, 07:17 PM
Sazza

Hello, sorry about the font!
June 25th 2007, 07:20 PM
Jhevon

Quote:

Originally Posted by Sazza

Hello, sorry about the font!

yup, all your love and happiness is too much for us!

just kidding, it's fine. just try to be happy and lovely in a more optically-friendly way :D
June 25th 2007, 07:49 PM
Sazza

haha yup =]
June 26th 2007, 10:13 PM
Sazza

Quote: Have you heard of proportions? A comparison of two ratios?

We've got to have like units. One 1 m = 100 cm. So the 1.5 m = 150 cm.

Just solve for x:...http://www.mathhelpforum.com/math-he...1713a3c5-1.gif

Does that mean the if i find the value of x, than i'm finding the amount? :confused:
90 divided by 3.6 x 150 = 3,790??
June 26th 2007, 10:24 PM
topsquark

Quote:

Originally Posted by Sazza

Quote: Have you heard of proportions? A comparison of two ratios?

We've got to have like units. One 1 m = 100 cm. So the 1.5 m = 150 cm.

Just solve for x:...http://www.mathhelpforum.com/math-he...1713a3c5-1.gif

Does that mean the if i find the value of x, than i'm finding the amount? :confused:
90 divided by 3.6 x 150 = 3,790??

Yes, if you find x you are finding the amount.

No to " 90 divided by 3.6 x 150 = 3,790"

$\frac{90}{3.6} = \frac{150}{x}$

To get rid of the fractions, multiply both sides by 3.6x, or just simply "cross multiply":

$90x = 150 \cdot 3.6 = 540$

$x = \frac{540}{90}$

$x = 6$

-Dan
June 27th 2007, 04:45 PM
Sazza

Quote:

Originally Posted by Jonboy

Just solve for x:... $\frac{90}{3.6}\,=\,\frac{150}{x}$

Make a proportion.

You should get:.. $\frac{153}{850}\,=\,\frac{x}{1350}$

so it would be: 153 divided by 850 x 1350 = 243??
June 27th 2007, 04:49 PM
Jhevon

Quote:

Originally Posted by Sazza

so it would be: 153 divided by 850 x 1350 = 243??

yes
June 27th 2007, 06:06 PM
Sazza

Okay thanks =] and i've been flipping through my mathematic books, because my teacher has hinted that they'll be asking about variables as in: 2a + 3a
so i thought i'd do some revision! Is a the coefficient of 2? i can't remember the name! :eek:
June 27th 2007, 06:12 PM
Sazza

rightio =] thanks, i'll be going to my exam now. My doom :eek: haha nah! Well i haven't memoried all the angles like isosolece, or revolution but i'll do my best! Wish me luck :rolleyes:
June 27th 2007, 06:16 PM
Jonboy

Quote:

Originally Posted by Sazza

rightio =] thanks, i'll be going to my exam now. My doom :eek: haha nah! Well i haven't memoried all the angles like isosolece, or revolution but i'll do my best! Wish me luck :rolleyes:

Haha. Hey, I know you can do it. Just some comprehensive studying and use logic then I'm sure you'll do fine. :cool:
June 27th 2007, 06:26 PM
Jhevon

the coefficient is the number that accompanies the variable, conventionally written in front of the variable.

so for 2a + 3a

the variable is a

the coefficients are 2 and 3

Good Luck!

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