I have the problem y=(8-9x)/(8-7x) and cannot solve it. If someone would give a few steps, it'd be greatly appreciated
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$\displaystyle \displaystyle\frac{8-9x}{8-7x} =\frac{9}{7}-\frac{16}{7(8-7x)} $
Or: $\displaystyle \frac{8- 9x}{9- 7x}= y$ multiply both sides by 9- 7x: 8- 9x= (9- 7x)y= 9y- 7xy Add 7xy to both sides and subtract 9 from both sides: 7xy- 9x= (7y- 9)x= 9y- 8 Finally, divide both sides by 7y- 9.
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