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Math Help - Algebra: Finding Inverses

  1. #1
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    Algebra: Finding Inverses

    I have the problem y=(8-9x)/(8-7x) and cannot solve it. If someone would give a few steps, it'd be greatly appreciated
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  2. #2
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    \displaystyle\frac{8-9x}{8-7x} =\frac{9}{7}-\frac{16}{7(8-7x)}
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  3. #3
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    Or:
    \frac{8- 9x}{9- 7x}= y
    multiply both sides by 9- 7x:
    8- 9x= (9- 7x)y= 9y- 7xy
    Add 7xy to both sides and subtract 9 from both sides:
    7xy- 9x= (7y- 9)x= 9y- 8

    Finally, divide both sides by 7y- 9.
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