It's been a while since I've done algebra (grad in neuro) so perhaps I'm missing something very basic but I was wondering if anyone can find the steps to solving this equation:

$\displaystyle (2)2^2^x-22+12^x=0$

Much Appreciated!

PS. the solution is x=~1.04 .. but I'm more interested in the steps to get there!

I've been able to expand $\displaystyle 12^x$ --> $\displaystyle 3^x2^2^x$ but not much further.. according to the problem only exponent laws should be used to get to the solution..