I understand Your reply fully, thanks:-)
But since there is an n on both sides the correct equation:
nLambda 1=(n+1)Lambda 2
with solution:
n=lambda 2/(lavmbda 1-lambda 2) has a different technique which I cant figure out. If You know how I would be very grateful
Do you realize how difficult it is to read your postings?
Why not learn to post in symbols? You can use LaTeX tags
[tex] n\lambda_1=(n+1)\lambda_2[/tex] gives .
It's pretty much basic algebra- you have to get n by itself so first you have to "free" it from the right side by using the "distributive" property: . At that point you have
Still trying to get n by itself, subtract from both sides:
Now use the "distributive" property again:
and, finally, divide both sides by .
That's essentially just what Plato did before.