I have to prove that if then identity is valid:
I have try to prove it.This what I have done:
So identity is not valid.
Am I right?
As in proving trig identities, here it is better to check first if the probvlem identity is true for a numerical substitution.Originally Posted by DenMac21
Try x=0 and y=2.
You get the LHS to be 13/4, while the RHS to be 7/2.
LHS <> RHS, hence, not an identity.
So no need to crack cranium for those x's and y's.