Please help solve this. My brain is blocked.
2x (x-1)^2 (2x+3) = 0
if you have several numbers being multiplied give zero, it means at least one of the numbers must be zero
$\displaystyle 2x (x - 1)^2 (2x + 3) = 0$
$\displaystyle \Rightarrow 2x = 0 \mbox { or } (x - 1)^2 = 0 \mbox { or } 2x + 3 = 0$
$\displaystyle \Rightarrow x = 0 \mbox { or } x = 1 \mbox { or } x = - \frac {3}{2}$
So there are three values of $\displaystyle x$ for which the above holds