t = time in hours wilbur travels
t - 2 = time in hours mary travels
wilbur's distance traveled = mary's distance traveled
33t = 55(t-2)
solve for t
Hi all;
I'm trying to solve the following problem I know the answer is 5hours I just need to know if I'm solving right.
Wilbur left the hardware store and traveledWilbur travel before Mary caught up?
toward the recycling plant at an average
speed of 33 km/h. Mary left two hours later
and traveled in the same direction but with
an average speed of 55 km/h. How long did
I've got (3)33 + 33(x) = 55 + 55(x) resulting x=2 which does result in 5hours is this right?
Thanks.