Can you finish it from here using simple index laws?
Spoiler:
First, although it may seem "picky", you don't have an equation here, you have an expression. (It isn't equal to anything.)
What do you want to do with the ? That is, what are you trying to do with the original expression? Simplify it? seems simple enough to me! You could, if you wanted, factor out an " ". so [tex]16n^{12}- n^2= n^2(16n^{10}- 1). If you really wanted to you could factor that further- is the difference of two squares and can be factored as . whether is "simpler" than is a matter of taste or, perhaps better, of what you wanted to do with it from here.